Fluorine, a chemical element with the symbol F and atomic number 9, is the lightest halogen and exist as a highly toxic diatomic gas with a pale yellow appearance at normal pressure and temperature. Fluorine is the most reactive chemical element with the highest electronegativity value of 3.98 according to the Pauli scale so that it can react with all other elements except helium, neon, and argon.
Elemental fluorine
and mostly all the fluorine compounds are produced from hydrogen fluoride (HF).
It is widely used as refrigerant gas (ferons), production of polymers
(fluoropolymers, PTFE), surfactants, agrichemical, and in many other applications.
You are here to
know valence electrons of fluorine atom, aren’t you? Don’t worry along with fluorine
valence electrons we will explain its valency also. But before that let’s have
some basic ideas about what these two terms are:
Difference Between Valence Electrons and Valency
Valence electrons
are the total number of electrons present in the outermost shell of an atom
(i.e. in outermost orbital). The valence electrons for a neutral atom are
always definite, it cannot be varied (more or less) in any condition for a
particular atom and may or may not be equal to its valency.
Valency is defined
as the total number of electrons, an atom can lose, gain, or share at the time
of bond formation to get a stable electronic configuration i.e. to complete an
octet. The valency of an atom can be variable in different compounds or
chemical reactions due to the different bonding circumstances. Most of the time
valency varies/changes due to change in oxidation and reduction states.
Fluorine (F) Valence Electrons
There are four
simple steps to find out the valence electrons for fluorine atom which are:
Step 1: Find the
Atomic Number
To find out the
atomic number of fluorine, we can use the periodic table. With the help of the
periodic table, we can easily see that the atomic number of fluorine is 9. As
its atomic number is 9, it has 9 protons, and for neutral fluorine, the number
of protons is always equal to the number of electrons i.e. has 9 electrons in
its nucleus.
Step 2: Write
Electron Configuration
Electron
configuration is the arrangement of electrons on the orbitals. The fluorine
atom has a total of 9 electrons so, we have to put 9 electrons in orbitals. The
electrons will be placed in different orbitals according to the energy level:
[1s, 2s, 2p, 3s, 3p, 4s, 3d, 4p, 5s, 4d, 5p, 6s, 4f, 5d, 6p, 7s, 5f]. Now,
Fluorine electron configuration F (9) = 1s22s22p5(complete configuration).
= [He] 2s22p5 (condensed configuration).
Step 3: Determine
Valence Shell
As we know, the valence shell of an atom can be found from the highest number of principle quantum numbers which are expressed in the term of n, and in [He] 2s22p5, the highest value of n is 2 so that the valence shell of fluorine is 2s22p5.
Step 4: Find
Valence Electrons
The total number of electrons present in the valence shell of an atom is called valence electrons, and there are a total of seven electrons present in the valence shell of fluorine (2s22p5). Thus, fluorine has seven valence electrons.
Also Read:
- Valence Electrons & Valency of Carbon (C).
- Valence Electrons & Valency of Hydrogen (H).
- Valence Electrons & Valency of Sulfur (S).
Valency of Fluorine (F)
There are many
different ways to find out the valency of an atom which reflects the ability of
an atom to bond with other atoms. Valence describes how easily an atom or a
free radical can combine with other chemical species. The valency of an atom is
determined based on the number of electrons lost, gained, or shared with
another atom at the time of bond formation.
An atom is said to
be stable when its outermost shells have eight electrons (except H & He).
If the total number of electrons in outermost shells is between one to four,
the atom has positive valency and if electrons are between four to eight, the
valency is calculated by subtracting from eight and valency will be zero. Atoms
having four outermost electrons possess both positive and negative valency, and
atoms having eight outermost electrons, valency will be zero (i.e. noble
gases).
Elements like fluorine
can reach the stable state (nearest inert gas configuration: Ne) by getting one
electron. So that the valency of fluorine is 1.
Mathematically, the
electronic configuration of fluorine is 2, 7. And as we know, if electrons in
outermost shell exceeds from 4, it should be subtracted from 8. So,
Electron
Configuration of fluorine (S) = 2, 7
We can see the outer
most shell of fluorine has 6 electrons so, have to subtract it from 8.
8 – 7 = 1
That’s why valency
of fluorine is 1.
Note: In general, fluorine
has a stable oxidation state of -1 most of the time but it can differ in
some compound like F2 and HOF where its oxidation state is 0 and +1
respectively. Do not confuse with -1 or something else (0 or +1) with positive
or negative signs, it is just an oxidation number that can vary from compound to
compound. But its valency is always 1 in any case.
In another sense, a
fluorine atom can form a maximum of one covalent bond in a chemical bonding (For
example: HF, SiF4, CF4, etc.), and that what valency is, the maximum ability to
form bonds with atoms at the time of chemical bonding.
We can also find
the valency of fluorine with the help of the periodic table. As fluorine
belongs to group 17 (17A or VIIA) along with chlorine (Cl), bromine (Br), and iodine
(I), and astatine (At). These group elements are also called halogens. All these
elements have a valency of one.
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